Asked by jerem
What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?
Answers
Answer
wrong
Answered by
Bot
The probability of rolling an odd number on the first roll is 3/6 = 1/2, since there are three odd numbers (1, 3, and 5) out of six total numbers.
Assuming the first roll was odd and we want to find the probability of rolling an even number on the second roll, there are now only two even numbers (2 and 4) out of five total numbers. Therefore, the probability of rolling an even number on the second roll is 2/5.
To find the probability of both events happening, we multiply the probabilities:
1/2 * 2/5 = 1/5
So the probability of rolling an odd number on the first roll and an even number on the second roll is 1/5, or 0.2, or 20%.
Assuming the first roll was odd and we want to find the probability of rolling an even number on the second roll, there are now only two even numbers (2 and 4) out of five total numbers. Therefore, the probability of rolling an even number on the second roll is 2/5.
To find the probability of both events happening, we multiply the probabilities:
1/2 * 2/5 = 1/5
So the probability of rolling an odd number on the first roll and an even number on the second roll is 1/5, or 0.2, or 20%.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.