20,0g MgCl2 and 20,0g NaCl are mixed together and dissolved in water to make up 2,00dm cube of solution. Calculate the concentration of the chloride ions in the solution

Answer 1

To calculate the concentration of chloride ions in the solution, we need to determine the moles of chloride ions present in the solution first.

First, let's calculate the moles of MgCl2:
Molar mass of MgCl2 = 24.305 g/mol + 2 * 35.453 g/mol = 95.211 g/mol

Moles of MgCl2 = 20.0 g / 95.211 g/mol = 0.20990 mol

Next, let's calculate the moles of NaCl:
Molar mass of NaCl = 22.990 g/mol + 35.453 g/mol = 58.443 g/mol

Moles of NaCl = 20.0 g / 58.443 g/mol = 0.342019 mol

Now, let's calculate the total moles of chloride ions in the solution:
Total moles of chloride ions = 2 * (0.20990 mol + 0.342019 mol) = 1.103818 mol

Finally, let's calculate the concentration of chloride ions in the solution:

Concentration (mol/dm^3) = Total moles of chloride ions / Volume of solution
Concentration (mol/dm^3) = 1.103818 mol / 2.00 dm^3

Concentration (mol/dm^3) ≈ 0.5519 mol/dm^3

Therefore, the concentration of the chloride ions in the solution is approximately 0.5519 mol/dm^3.