20.00mL of 0.55M CH3COOH solution is mixed with 9.95mL of 1.0M NaHCO3 solution.
The reaction occurring is CH3COOH + NaHCO3 --> CH3CHOO + Na + H2O +CO2.
Which is the limiting reagent in this reaction?
2 answers
The next question is, how may grams of CO2 will be produced as a result?
I work these limiting reagent (LR) problems the long way.
mols CH3COOH = M x L = ?
mols NaHCO3 = M x L = ?
Using the coefficients in the balanced equation, convert mols CH3COOH to mols CO2.
Do the same and convert mols NaHCO3 to mols CO2.
It is likely these two numbers will not be the same; the correct value in LR problems is ALWAYS the smaller value and the reagent responsible for that number is the LR.
For the next problem, convert to mols CO2 using the smller number of mols CO2.
grams CO2 = mols CO2 x molar mass CO2.
mols CH3COOH = M x L = ?
mols NaHCO3 = M x L = ?
Using the coefficients in the balanced equation, convert mols CH3COOH to mols CO2.
Do the same and convert mols NaHCO3 to mols CO2.
It is likely these two numbers will not be the same; the correct value in LR problems is ALWAYS the smaller value and the reagent responsible for that number is the LR.
For the next problem, convert to mols CO2 using the smller number of mols CO2.
grams CO2 = mols CO2 x molar mass CO2.
1 answer