deltaL=L*coeff*delta temp
deltaL=L 19E-6 * 180
deltaL/L=19E-6 * 180
Now, L+deltaL=20.00 cm
deltaL/L +1=20.00/L
19E-6 * 180+1=20.00/L
L=20.00/(19E-6 * 180+1) and that answer is above.
20.00 cm of space is available. How long a piece of brass at 20°C can be put there and still fit at 200°C? Brass has a linear expansion coefficient of 19 × 10^-6/C°.
19.93 cm
19.69 cm
19.50 cm
19.09 cm
1 answer