2: Y^5 x y^14=

A: 2y^19
B: y^60
C: y^19
D: 2y^60

3: w^12 ÷ w^18

A: w^30
B: w^-30
C: w^6
D: w^-6

4: Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?

A: 4 x 2^3 ÷ 2^3
B: 2 x 2^3 ÷ 2^4
C: 3 x 2^3 ÷ 2^4
D: 3 x 2^4 ÷ 2^4

5: Taylor completed the problem below. Describe and correct the error in the problem.

2^-4 = -2 x -2 x -2 x -2 =16

A: Taylor changed the negative exponent to a negative base. *****
B: Taylor did not multiply correctly. The answer should be 16.
C: Taylor made the answer positive. It should be -16.
D: Taylor did not multiply by -1. The problem should be 2^-4 = (-1) 1 ÷ 2^4 = (-1) 1 ÷ 2 • 2 • 2 • 2 = 1/16

I only know the answer to the first and last question (1 and 5) someone please help with the rest.. thank you :)

1 answer

2. Add the exponents, y stays as is.
3. Subtract the exponents, w stays as is, but your answer will be in a fraction.
4. Try out each answer choice, and see what makes sense and is correct.
5. Check again.