x^2 + y^2 + 8x + 2y + 8 = 0
x^2+8x+(8/2)^2+y^2+2y+(2/2)^2=-8+(8/2)^2
+(2/2)^2.
x^2+8x+16 + y^2+2y+1 = -8+16+1
Eq: (x+4)^2 + (y+1)^2 = 9
C(-4,-1).
r2 = 9
r = +-3
2. Write the equation of the circle in standard form. Find the center, radius, intercepts, and graph the circle.
x2+y2+8x+2y+8=0
1 answer