a^2 + s^2 = b^2 usual version for hypotenuse(diagonal) of rectangle d given sides a and b
but if a = b = s
then
s^2+s^2 = d^2
so
2 s^2 = d^2
d = s sqrt 2
2. Which special version of the Pythagorean Theorem can you use to find the length of any square's diagonal, d, using only the length of its side, s?
1 answer