2. When traveling down the road at a constant speed of 55 mph, 26.4 m/s, the tangential velocity of the wheels is also 55 mph. If a car tire is 65.0 cm in diameter, then;

a. What is the period and frequency of the spinning car tire?
b. What is the centripetal acceleration of a rock stuck in the tire’s tread ?

1 answer

circumfance=PI*r^2=PI*(.65/2)^2

period=cir/dpeed=above/26.4 sec

freq= 1/period

ang freq=2PI*freq

centripetal acc= w^2*radius