To work through the problems step by step:
-
First, you can graph the function \( f(x) = x^2 - 3x + 2 \) in Desmos. This will help you visualize the function and check points.
-
To find \( f(0) \): \[ f(0) = 0^2 - 3(0) + 2 = 0 - 0 + 2 = 2 \] So, \( f(0) = 2 \).
-
To find \( f(1) \): \[ f(1) = 1^2 - 3(1) + 2 = 1 - 3 + 2 = 0 \] So, \( f(1) = 0 \).
-
To find \( f(2) \): \[ f(2) = 2^2 - 3(2) + 2 = 4 - 6 + 2 = 0 \] So, \( f(2) = 0 \).
-
The y-intercept occurs where \( x = 0 \). Since we already calculated \( f(0) \), the y-intercept is at the point \( (0, 2) \).
Summary of Answers:
- \( f(0) = 2 \)
- \( f(1) = 0 \)
- \( f(2) = 0 \)
- The y-intercept is \( (0, 2) \) as an ordered pair.
You can now enter these answers into your assignment. If you have any further questions or need additional help, feel free to ask!