2. The length of a rectangle is four meters less than twice its width.

If the area of the rectangle is 96 m^2, what is the length and the width?

(3 points)
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An expression for the length of the rectangle in terms of the width would be Response area

The formula for the area of a rectangle is Response area

Using trial and error, if the area is 96 m^2, then the length and width are Response area?

1 answer

To solve the problem step by step:

  1. Expression for the length of the rectangle in terms of the width:

    • Let the width be \( w \).
    • Given that the length is four meters less than twice the width, the expression for the length \( l \) is: \[ l = 2w - 4 \]
  2. Formula for the area of a rectangle:

    • The area \( A \) of a rectangle is given by the formula: \[ A = l \times w \]
  3. Using the area of the rectangle to find the dimensions:
    Since the area is given as 96 m², we can set up the equation: \[ A = (2w - 4) \times w = 96 \]

    Simplifying this: \[ 2w^2 - 4w = 96 \] Rearranging gives: \[ 2w^2 - 4w - 96 = 0 \] Dividing through by 2 simplifies it to: \[ w^2 - 2w - 48 = 0 \] Now we will factor the quadratic: \[ (w - 8)(w + 6) = 0 \] Setting each factor to zero gives us: \[ w - 8 = 0 \quad \text{or} \quad w + 6 = 0 \] Thus, \( w = 8 \) (valid, since width can't be negative) or \( w = -6 \) (invalid).

    So, the width \( w = 8 \) meters. Now, substituting \( w \) back to find length \( l \): \[ l = 2(8) - 4 = 16 - 4 = 12 \text{ meters} \]

  4. Conclusion:

    • The width is 8 meters.
    • The length is 12 meters.

Now, we can fill in the responses for your specific input sections:

  • An expression for the length of the rectangle in terms of the width would be: 2w - 4
  • The formula for the area of a rectangle is: A = l × w
  • Using trial and error, if the area is 96 m², then the length and width are: Length = 12 m, Width = 8 m.