for ease of reading, I'll use x and y for length and width
Hmmm. It appears you meant to say
The length l of a rectangle is decreasing at the rate of 3 cm/sec,
while its width w is increasing at the rate of 3 cm/sec.
the diagonal
d^2 = x^2 + y^2
so at the given moment,
d = 3√29
area a = 90
area a = xy
da/dt = y dx/dt + x dy/dt
= 6(-3) + 15(3) = 27 cm^2/s
see what you can do with the perimeter
I have no idea what the (c) part is
It's not my job to figure out what you mean.
It's your job to say it so clearly you cannot be misunderstood.
2. The length / of a rectangle is decreasing at the rate of 3 cm/sec,
one diagonal at the instant when l = 15 and w = 6.
rates of change of (a) the area, (b) the perimeter, (c) the length of
while its width w is increasing at the rate of 3 cm/sec. Find the
1 answer
1 answer