2. Suppose a chemistry student made 2000. mL of 6.00 M HCl. He accidently spilled half of this solution on the floor. What is the Molarity of HCL left in the beaker? Explain the answer...

Question

- for this problem, would I use the eq'N, M1V1=M2V2.

3. What is the molarity of a sol'n that contains 28.5 g of KOH in 2.00 L of sol'n?

5. If 500. ml of 2.0 M H2SO4 is diluted with water to a volume of 1.00 L, what is the molarity of the new solution.

Answer 1

2. The lost solution does not change the molarity of what is left in the beaker.
3. M=(28.5/40)/2

4. you are diluting it by a factor of 2. New molarity=1M

Answer 2

2. I still don't get this or is it the same equation.
3. Answer: 0.254 M KOH
5. Am I still using the equation?

Answer 3

Is #5's answer: 1.0 M H2SO4?
what about #2?