To solve the equation \( x^2 = 289 \) by inspection, we need to find the values of \( x \) that satisfy this equation.
Taking the square root of both sides, we find: \[ x = \pm \sqrt{289} \] Calculating the square root: \[ \sqrt{289} = 17 \] Thus, the two solutions are: \[ x = 17 \quad \text{and} \quad x = -17 \]
Since we need to enter the lesser number first, the solutions are: \[ {-17, 17} \]