The given equation is 2√x = x.
First, we can square both sides to eliminate the radical:
(2√x)^2 = x^2
4x = x^2
Now we can simplify by subtracting 4x from both sides:
0 = x^2 - 4x
Factoring out an x:
0 = x(x - 4)
Therefore, the value of x can either be 0 or 4, since either x = 0 or x - 4 = 0. However, we need to check if either of these solutions work in the original equation:
If x = 0, then 2√0 = 0, which is true.
If x = 4, then 2√4 = 4, which is also true.
Therefore, the solutions are x = 0 or x = 4.
2 radical x = x
What is the value of x?
Please explain
5 answers
I am having trouble understanding how x^2 - 4x = 0
In this step, we are trying to factor the equation x^2 - 4x = 0, so we can easily find the values of x that make the equation true.
We can factor x out of the equation to get:
x(x - 4) = 0
Now we have two factors: x and (x - 4). These two factors multiply together to give us the original equation.
From the zero product property, we know that if the product of two factors equals zero, then at least one of the factors must be zero.
In this case, that means either x = 0 or (x - 4) = 0, which gives us x = 4. These are the two solutions to the equation.
So x^2 - 4x = 0, which we can factor to get x(x - 4) = 0, and we can solve for x by setting each factor equal to zero.
We can factor x out of the equation to get:
x(x - 4) = 0
Now we have two factors: x and (x - 4). These two factors multiply together to give us the original equation.
From the zero product property, we know that if the product of two factors equals zero, then at least one of the factors must be zero.
In this case, that means either x = 0 or (x - 4) = 0, which gives us x = 4. These are the two solutions to the equation.
So x^2 - 4x = 0, which we can factor to get x(x - 4) = 0, and we can solve for x by setting each factor equal to zero.
Thank you!
You're welcome! Feel free to ask if you have any other questions.