To find the length of one side of the rhombus QRST, we can use the properties of rhombuses and the Pythagorean theorem.
In a rhombus, the diagonals bisect each other at right angles. This means that point U is the midpoint of both diagonals QS and RT. Given the lengths of the diagonals:
- QS = 30, so each half (QU and US) = 30/2 = 15.
- RT = 16, so each half (RU and UT) = 16/2 = 8.
Now we can use these segments to form a right triangle, where one side is 15 (QU) and the other side is 8 (RU). Let’s denote the length of one side of the rhombus as \( s \).
Using the Pythagorean theorem:
\[ s^2 = QU^2 + RU^2 \]
Substituting in the lengths:
\[ s^2 = 15^2 + 8^2 \]
Calculating the squares:
\[ s^2 = 225 + 64 \] \[ s^2 = 289 \]
Now taking the square root:
\[ s = \sqrt{289} = 17 \]
Thus, the length of one side of the rhombus is 17.
The correct response is 17.