2 NH3 (g) ----> N2 9g) + 3 H2 (g)

at equilibrium, [NH3] = 0.0227 M, [N2] = 0.119 M, and [H2] = 0.346 M. Calculate Kc for the reaaction at this temperature

1 answer

For a general reaction,
aA + bB ---> cC
the equilibrium constant, Kc, is given by
Kc = [products] / [reactants] = (C)^c / ( (A)^a * (B)^b )

The reaction given is: 2 NH3 ---> N2 + 3 H2
Thus,
Kc = (N2) * (H2)^3 / (NH3)^2
Plug in the concentration values given, and solve for Kc. Don't forget the units.

hope this helps~ `u`