2 NaOH + CuSO4  Na2SO4 + Cu(OH)2

Question

100g of Cu(OH)2 is needed. Assuming 100% yield, how much of 1M NaOH and 0.5M CuSO4 must be used in mL?

Answer 1

How many mols Cu(OH)2 do you need? That's mols = g/molar mass = 100/97.56 = approx 1 mol but you need to do it more accurately.
Convert mols Cu(OH)2 to mols NaOH = twice that = about 2 mol (again, do it more accurately).
M NaOH = mols/L. You know mols NaOH and M NaOH, solve for L NaOH and convert to mL.

Do the same to convert mols Cu(OH)2 to mols CuSO4 then M = mols/L. Finally, convert L CuSO4 to mL.