2 mol ammonia (NH3) gas is collected in a separate gas cylinder which has a volume of 25 dm3. The pressure of the gas is 195,89 kPa. The temperature of the gas inside the cylinder is

Answer 1

25°C, which is equivalent to 298 K.

To find the number of moles of ammonia in the cylinder, we use the ideal gas law equation:

PV = nRT

Where:
P = pressure = 195.89 kPa = 195.89 x 10^3 Pa
V = volume = 25 dm^3 = 25 x 10^-3 m^3
n = number of moles
R = gas constant = 8.31 J/(mol·K)
T = temperature = 298 K

Plugging in the values, we get:

(195.89 x 10^3) x (25 x 10^-3) = n x 8.31 x 298

4872.25 = 2481.18n

n = 1.964 moles

Therefore, there are 1.964 moles of ammonia gas in the cylinder.