2CH4 + 2NH3 +3O2 Arrow 2HCN + 6H2O
CH4 is going to be used up making it the limited reagent
13.5 g CH4
10gNH3(1 mole NH3)(2 mole HCN)
(14.01g NH3)(2 mole NH3)
=.714 mole HCN
Do the same for Ammonia and you get .499 mole HCN or .50
2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:
CH4 + NH3 + O2 HCN + H2O
You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer the following questions:
• What is the balanced equation for this reaction?
• Which reagent is limiting? Explain why.
• How many grams of hydrogen cyanide will be formed?
1 answer