without some grouping symbols, I know what you wrote.
my guess is you meant this
2*ln(e)= ln ((7/x)^.5 ) - 2ln(e)
2*1=1/2 ln (7/x) -2
4=1/2 ln(7/x)
ln(7/x)=8
take the antilog
7/x=e^8
then solve for x
2 ln e = ln sq rt. 7/x-2 ln e
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