2.) How much heat must be absorbed at 1357 K to melt a bar of copper (80 * 10 * 12 cm) assume d = 8.93 g/cm^3.
The normal boiling point is 1357 K, and heat of fusion is 13.05 KJ/mol.
2 answers
Answered below.
heatabsorved= masscopper*Heatfusion
remembering the mass= volume*density.
Watch your units. You will have to change either mass to moles, or heatfusion to kJ/gram.
remembering the mass= volume*density.
Watch your units. You will have to change either mass to moles, or heatfusion to kJ/gram.
3 answers