here,
first term(a)=15
last Term(l)=57
Common difference(l)=3
n terms (n)=?
by the formula,
l= a+(n-1)d
or, 57= 15+(n-1)3
or, 57-15=(n-1)3
or, 42/3= n-1
or, 14= n-1
or, 14+1= n
or, 15= n
there for n terms (n)= 15
(2) How Many Terms Has The A.P Whose First Term Is 15 Aod The Last Term Is 57 Given That The Common Difference Is 3?
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I need answer
His the answer 0
4
15