2. How is the graph of y = –2x² – 5 different from the graph of y = –2x²? (1 point)

Question

It is shifted 5 units up.
It is shifted 5 units down.
It is shifted 5 units left.
It is shifted 5 units right.
3. A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation
y = –0.04x
2
+ 8.3x + 4.3 , where x is the horizontal distance, in meters, from the starting point on the roof and y is the
height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?
Round your answer to the nearest hundredth meter. (1 point)
208.02 m
416.03 m
0.52 m
208.19 m
4. A physics student stands at the top of a hill that has an elevation of 56 meters. He throws a rock and it goes up
into the air and then falls back past him and lands on the ground below. The path of the rock can be modeled by the
equation y = –0.04x² + 1.3x + 56 where x is the horizontal distance, in meters, from the starting point on the top of the
hill and y is the height, in meters, of the rock above the ground.
How far horizontally from its starting point will the rock land? Round your answer to the nearest hundredth. (1 point)
56.00 m
24.54 m
57.04 m
57.26 m
How many real-number solutions does the equation have?
5. –7x² + 6x + 3 = 0 (1 point)
one solution
two solutions
no solutions
infinitely many solutions
6. How many real number solutions does the equation have?
y = 3x² + 18x + 27 (1 point)
one solution
two solutions
no solutions
infinitely many solutions
9. Find the solutions to the system.
y = x² – 5x + 2
y = –6x + 4 (1 point)
(2, 8) and (−1, 2)
(−2, 8) and (1, −2)
(−2, 16) and (1, −2)
no solutions
10. Find the solutions to the system.
y = x² + 8x + 2
y = 7x + 4 (1 point)
(−2, −10) and (1, 11)
(2, 10) and (−1, −11)
(−2, −34) and (1, 11)
no solutions
11. If an object is dropped from a height of 200 feet, the function h(t) = –16t² + 200 gives the height of the object
after t seconds. Approximately, when will the object hit the ground? (1 point)
200.00 seconds
184.00 seconds
3.54 seconds
0.78 seconds
12. A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t seconds is
given by the function h(t) = –16t² + 32t + 6. How long does it take the ball to reach its maximum height? What is the
ball’s maximum height? Round to the nearest hundredth, if necessary. (1 point)
Reaches a maximum height of 22 feet after 1.00 second.
Reaches a maximum height of 22 feet after 2.00 seconds.
Reaches a maximum height of 44 feet after 2.17 seconds.
Reaches a maximum height of 11 feet after 2.17 seconds.
13. A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t
seconds is given by the function h = –16t² + 148t + 30. How long does it take the boulder to reach its maximum
height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary. (1 point)
Reaches a maximum height of 30 feet after 9.25 second.
Reaches a maximum height of 640.5 feet after 4.63 seconds.
Reaches a maximum height of 1,056.75 feet after 4.63 seconds.
Reaches a maximum height of 372.25 feet after 4.63 seconds

Answer 1

2. Shifted 5units down.

5. -7x^2 + 6x + 3 = 0
Use Quadratic formula and get 2 solutions : -0.354, and 1.211.

6. Y = 3x^2 + 18x + 27 = 0
x^2 * 6x + 9 = 0
(x+3)(x+3) = 0
x+3 = 0, x = -3.
x+3 = 0, X = -3.
2 solutions : -3, and -3.

11. Use Quad. Formula and get 3.54 s.

12. V = Vo + g*t = 0 @ max. ht.
32 - 32*t = 0
32t = 32
t = 1 s. = Time to reach max ht.

hmax = -16t^2 + 32t + 6
hmax = -16*1^2 + 32*1 + 6=22 Ft. after
1 second.

13. Same procedure as #12.