2 H2O (ℓ) ⇆ H3O+(aq) + OH-(aq)

Question

Kw = 4.57 x 10^-15 at 15 °C.
Calculate the pH of 0.10 M NaOH at this temperature.

Answer 1

Kw = 4.57E-15 = (H3O^+)(OH^-)
(H2O^+) = (OH^-)
(H3O^+) = sqrt(Kw) and convert to pH.