The formula for voltage gain of a Band pass filter is:
A = (R5/R1) * (1/(R2*C1*C2*R3 + R2*C1*R5 + R3*C2*R6 + 1))
Plugging in the given values,
A = (47KΩ/10KΩ) * (1/((10KΩ*68nF*68nF*5.6KΩ) + (10KΩ*68nF*47KΩ) + (5.6KΩ*68nF*47KΩ) + 1))
A = 0.4019 or 20log(0.4019) = -9.42 dB
The overall voltage gain of the 4th order Band pass filter is -9.42 dB, which is approximately 9.4 dB (option c).
2. Determine the overall voltage gain (in dB) of the 4th order Band pass filter. Given R7 = 8.9kΩ and R3 = 5.6KΩ.
C1 = 68nF
C2 = 68nF
C5 = 150nF
C6= 150nF
R1 = 10KΩ
R2 = 10KΩ
R4 = 10KΩ
R5 = 47KΩ
R6 = 47KΩ
R8 = 10KΩ
The options are:
a) 10.8 dB
b) 3.2 dB
c) 9.4 dB
d) 6 dB
1 answer