2 cyclists start from the same point and ride in opposite directions. 1 rides twice as fast as the other. In 3 hours they are 90km apart. What is the rate of each cyclist? I figured out the answer is 20km/h and 10km/h. What I don't know and need help with is how to write the equations? If anyone could help me with this it would be much appreciated. Thank You

Answer 1

a = 2 b

3(a + b) = 90

Answer 2

Thank Scott but I did figure out the answer I just don't know how to write the equation for it, can you show me the equation? Thank You again

Answer 3

speed of slower rider --- x km/h
speed of faster rider ---- 2x km/h

distance gone by slower = 3(x) = 3x
distance gone by faster = 3(2x) = 6x

3x + 6x = 90
9x = 90
x = 10

rate of slower rider = 10 km/h
rate of faster rider = 2(10) = 20 km/h