two moles of benzene yield 6542kJ
so how many moles do you have? Ans 8.88/78.14
so the heat produced is 6542*(8.88/(2*78.14) kJ=371kj
heat produced=masswater*c*(Tf-22.5) solve for Tf
I get about a 14C rise in temp. Watch units, kj,kg,g
2 C6H6 + 15 O2 → 12 CO2 + 6 H2O ΔHrxn = 6542 kJ/rxn
If 8.88 g of C6H6 (FW = 78.114 g/mol) is burned and the heat produced from the reaction is used to heat 6354 g of water at 22.5o C, what is the final temperature of the water (swater = 4.184 J/g C)? (Write answer to 1 place past the decimal point)
1 answer
1 answer