2. A stone that starts from rest is in free fall for 8.00s. What is the stone's displacement during this time?

1 answer

The displacement of the stone during free fall can be calculated using the formula:

displacement = (1/2) * acceleration * time^2

The acceleration due to gravity (g) is approximately 9.8 m/s^2.

Given that the stone is in free fall for 8.00s, we can substitute the values into the formula:

displacement = (1/2) * 9.8 * (8.00)^2

displacement = (1/2) * 9.8 * 64

displacement = 313.6 m

Therefore, the stone's displacement during this time is 313.6 meters.