2.78g NaHCO3 dissolve in enough water to make 200.0ml of solution

Answer 1

To find the molarity of the NaHCO3 solution, we need to first calculate the number of moles of NaHCO3 present in 2.78g of the compound:

Molar mass of NaHCO3 = 84.0066 g/mol

Number of moles of NaHCO3 = mass / molar mass
= 2.78g / 84.0066 g/mol
= 0.0331 mol

Now, we can calculate the molarity (M) of the NaHCO3 solution using the following formula:

Molarity = number of moles / volume of solution in liters

Volume of solution = 200.0ml = 0.2 L

Molarity = 0.0331 mol / 0.2 L
= 0.1655 M

Therefore, the molarity of the NaHCO3 solution is 0.1655 M.