r^2 = x^2+y^2 = 40
r = √40
tanθ = y/x = 6/-2 = -3
Note that the point is in QII, so θ = π-arctan(3) ≈ 1.892
So, (-2,6) = (2√10, 1.892)
(-2,6) is placed in the Cartesian coordinate system. convert to polar coordiantes in degrees
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