First, we need to find the number of moles of sodium chloride (NaCl) present in 2.54 grams.
Molar mass of NaCl = 58.44 g/mol (23g for sodium + 35.44g for chlorine)
Number of moles = mass / molar mass
Number of moles = 2.54 g / 58.44 g/mol = 0.0435 mol (rounded to 4 decimal places)
Now, we need to find the volume of the solution in cubic decimeters (dm³).
Given that the solution was made up to 100 cm³, we have:
1 dm³ = 1000 cm³
100 cm³ = 0.1 dm³
Now, we can find the concentration in moles per cubic decimeter (mol/dm³):
Concentration = number of moles / volume
Concentration = 0.0435 mol / 0.1 dm³ = 0.435 mol/dm³
So, the concentration of the solution is 0.435 mol/dm³.
2.54g of sodium chloride were dissolved in water and the solution made up to 100cm cube. What is the concentration of the solution in mole per decimeter cube?
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