-2/5*3/10

7 answers

To multiply the fractions \(-\frac{2}{5}\) and \(\frac{3}{10}\), you multiply the numerators together and the denominators together:

\[ -\frac{2}{5} \times \frac{3}{10} = \frac{-2 \times 3}{5 \times 10} = \frac{-6}{50} \]

Next, you can simplify \(\frac{-6}{50}\). Both 6 and 50 can be divided by 2:

\[ \frac{-6 \div 2}{50 \div 2} = \frac{-3}{25} \]

So, \(-\frac{2}{5} \times \frac{3}{10} = -\frac{3}{25}\).

4* -5/8

To multiply \(4\) by \(-\frac{5}{8}\), you can treat \(4\) as a fraction, which is \(\frac{4}{1}\).

Now, perform the multiplication:

\[ 4 \times -\frac{5}{8} = \frac{4}{1} \times -\frac{5}{8} = \frac{4 \times -5}{1 \times 8} = \frac{-20}{8} \]

Next, simplify \(\frac{-20}{8}\) by finding the greatest common divisor (GCD) of 20 and 8, which is 4:

\[ \frac{-20 \div 4}{8 \div 4} = \frac{-5}{2} \]

So, \(4 \times -\frac{5}{8} = -\frac{5}{2}\).

-19.3*6

To multiply \(-19.3\) by \(6\), simply perform the multiplication:

\[ -19.3 \times 6 = -115.8 \]

So, \(-19.3 \times 6 = -115.8\).

-2 1/2* -1 3/5

To multiply the mixed numbers \(-2 \frac{1}{2}\) and \(-1 \frac{3}{5}\), we first need to convert them into improper fractions.

  1. Convert \(-2 \frac{1}{2}\) to an improper fraction:

    • Multiply the whole number \(2\) by the denominator \(2\): \(2 \times 2 = 4\).
    • Add the numerator: \(4 + 1 = 5\).
    • Since the original number is negative, we have: \[ -2 \frac{1}{2} = -\frac{5}{2} \]
  2. Convert \(-1 \frac{3}{5}\) to an improper fraction:

    • Multiply the whole number \(1\) by the denominator \(5\): \(1 \times 5 = 5\).
    • Add the numerator: \(5 + 3 = 8\).
    • Since the original number is negative, we have: \[ -1 \frac{3}{5} = -\frac{8}{5} \]
  3. Now multiply the two improper fractions: \[ -\frac{5}{2} \times -\frac{8}{5} \]

  4. Multiply the numerators and denominators: \[ = \frac{5 \times 8}{2 \times 5} = \frac{40}{10} \]

  5. Simplify the fraction: \[ \frac{40}{10} = 4 \]

So, \(-2 \frac{1}{2} \times -1 \frac{3}{5} = 4\).