To solve the equation \(-2(3x - 3) + 4x - 4 = 0\), follow these steps:
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Distribute \(-2\) to both terms inside the parentheses: \[ -2(3x) + -2(-3) = -6x + 6 \] So the equation becomes: \[ -6x + 6 + 4x - 4 = 0 \]
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Combine like terms: \[ (-6x + 4x) + (6 - 4) = -2x + 2 = 0 \]
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Now, isolate \(x\): \[ -2x + 2 = 0 \] Subtract 2 from both sides: \[ -2x = -2 \]
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Divide by \(-2\): \[ x = 1 \]
So, the solution to the equation is: \[ x = 1 \]