2(3r+4)-3(r+1)=11

Answer 1

To solve the equation 2(3r + 4) - 3(r + 1) = 11, we need to distribute the coefficients before combining like terms.

Starting with the left side of the equation:

2(3r + 4) becomes 6r + 8.
-3(r + 1) becomes -3r - 3.

So the equation now reads:

6r + 8 - 3r - 3 = 11.

Combining like terms, we get:

6r - 3r + 8 - 3 = 11,
3r + 5 = 11.

Next, we isolate the variable by subtracting 5 from both sides of the equation:

3r + 5 - 5 = 11 - 5,
3r = 6.

Dividing both sides by 3, we find:

3r/3 = 6/3,
r = 2.

Therefore, r = 2 is the solution to the equation 2(3r + 4) - 3(r + 1) = 11.