2(2x-8)-8x (greater than <) 0

1 answer

Let's solve the inequality \( 2(2x - 8) - 8x < 0 \).

  1. Expand the left-hand side: \[ 2(2x - 8) = 4x - 16 \] So the inequality becomes: \[ 4x - 16 - 8x < 0 \]

  2. Combine like terms: \[ 4x - 8x - 16 < 0 \] This simplifies to: \[ -4x - 16 < 0 \]

  3. Add 16 to both sides: \[ -4x < 16 \]

  4. Divide by -4 (remember to reverse the inequality sign): \[ x > -4 \]

Thus, the solution to the inequality is: \[ x > -4 \]