(2-√2)/(3+√2)
can you plz tell me how to solve it? plz hurry up
3 answers
for god sake plz help me.
i think the answer may be this
(2-√2)/(3+√2)
(2-√2)(3-√2)/(3+√2)(3-√2)
6-2√2-3√2+2/3*3-√2*√2
8-5√2/9-2
8-5√2/7
2√2-5√2/7
=-3√2/7
(2-√2)/(3+√2)
(2-√2)(3-√2)/(3+√2)(3-√2)
6-2√2-3√2+2/3*3-√2*√2
8-5√2/9-2
8-5√2/7
2√2-5√2/7
=-3√2/7
(2-√2)/(3+√2)
=(2-√2)/(3+√2) * (3-√2)/(3-√2)
= (6 -2√2 - 3√2 + 2)/(9-2)
= (8 - 5√2)/7
=(2-√2)/(3+√2) * (3-√2)/(3-√2)
= (6 -2√2 - 3√2 + 2)/(9-2)
= (8 - 5√2)/7