You made a typo; the atomic mass of Ag is 107.8(rounded). This is a limiting reagent (LR) problem and the way you know that is because amounts are given for BOTH reactants.
2Ag + S ==> Ag2S
mols Ag = 2.16/atomic mass Ag = ?
mols S = grams/atomic mass S = ?
Using the coefficients in the balanced equation, convert mols Ag to mols Ag2S.
Do the same and convert mols S to mols Ag2S.
It is likely that the two values for mols Ag2S will not be the same which means one is wrong. The correct value in LR problems is ALWAYS the smaller value and the reagent responsible for that lower values is called the LR.
Now take the smaller number and convert to grams Ag2S.
mols Ag2S x molar mass Ag2S = grams Ag2S.
2.16 grams of silver react with 3.20 grans of sulfur.Caculate the mass of silver sulfide produced
(mass of ag=108.8g/mole)
1 answer
1 answer