2,105

Question

has that could be split equally into 5
groups, which is 4
. He then subtracted the
hundreds used (4
hundreds x ×5
) from the 21
hundreds he started with, leaving
hundred remaining. He regrouped the hundred to tens, showing
tens. Of those,
tens can be put into each of the 5
groups, so he noted this in the tens place of the quotient and then subtracted the tens used. This left only
ones remaining, which can be divided so there is
one in each of the 5
groups. He noted this in th
e ones place of the quotient and subtracted the ones used. There was
remaining at the end.

Answer 1

It looks like you're describing the long division process of dividing the number 2,105 by 5. Let's break this down step by step.

1. Divide the Hundreds:

   • Start with 2,105. We have 2 in the thousands place, 1 in the hundreds place, 0 in the tens place, and 5 in the ones place.
   • We need to split it into 5 groups.
   • First, look at the hundreds. We have 21 hundreds (2,100).
   • 21 hundreds can be split into 5 groups where \(21 \div 5 = 4\) (which represents 4 complete groups since 5 x 5 = 20).
   • So, 4 groups have been formed, which accounts for \(4 \times 5 = 20\) hundreds.
   • This leaves us with \(21 - 20 = 1\) hundred remaining.

2. Regrouping the Hundreds:

   • Now we regroup this remaining 1 hundred into tens. Since 1 hundred equals 10 tens, we now have 10 additional tens to work with.
   • This means we currently have \(10\) tens plus the \(0\) tens we originally had, totalling \(10\) tens.

3. Divide the Tens:

   • Now, we divide these \(10\) tens into the \(5\) groups.
   • So, \(10 \div 5 = 2\), meaning we can put 2 tens into each group.
   • We then use \(2 \times 5 = 10\) tens, and if we subtract this from 10, we are left with \(10 - 10 = 0\) tens remaining.

4. Ones:

   • Now, we look at the ones. We started with 5 ones.
   • Since we have 0 tens remaining, we have \(5\) ones to work with.
   • Dividing these \(5\) ones by \(5\) groups gives us \(5 \div 5 = 1\), so there is 1 one in each group.
   • We note this in the ones place of the quotient. The \(5 - 5 = 0\) means we have \(0\) ones remaining.

5. Final Distribution:

   • So, after going through all this, we arrive at a complete quotient for dividing \(2,105\) by \(5\):
     • The hundreds place in the quotient is 4.
     • The tens place in the quotient is 2.
     • The ones place in the quotient is 1.
   • This means the final answer to \(2,105 \div 5\) is 421 with \(0\) remaining.

In conclusion, \(2,105\) divided by \(5\) yields a quotient of \(421\) with no remainder.