2.1

Simplify fully, without the use of a calculator:
2.1.2
5^2π‘₯+1+2.5^2π‘₯βˆ’1 /2.5^2π‘₯
(3)

3 answers

To simplify the given expression:

5^2π‘₯+1 + 2.5^2π‘₯-1 / 2.5^2π‘₯

First, we can rewrite 2.5 as 5/2:

5^2π‘₯+1 + (5/2)^2π‘₯-1 / (5/2)^2π‘₯

Now we can use the properties of exponents to simplify:

(5^(2π‘₯) * 5^1 + 5^(2π‘₯) * (5/2)^(-1)) / (5/2)^(2π‘₯)

(5^(2π‘₯+1) + 5^(2π‘₯) * (2/5)^(1)) / (5/2)^(2π‘₯)

(5^(2π‘₯+1) + 5^(2π‘₯) * 2/(5^2)) / (5/2)^(2π‘₯)

(5^(2π‘₯+1) + 5^(2π‘₯) * 2/25) / (5/2)^(2π‘₯)

Now we can simplify further if needed, but this is the fully simplified form of the expression.
how can you call that final mess "simplified"?
I suspect the question has been mangled, since
(5/2)^2π‘₯-1 / (5/2)^2π‘₯ = 5^-1 = 1/5
so the whole thing is just
5^2π‘₯+1 + 1/5
I doubt this was the original intent
Apologies for the confusion in my previous response. Let me simplify the expression correctly.

Given expression:
(5^2π‘₯+1 + 2.5^2π‘₯-1) / 2.5^2π‘₯

Rewriting the expression with 2.5 as 5/2:

(5^(2π‘₯+1) + (5/2)^(2π‘₯-1)) / (5/2)^(2π‘₯)

Using the property of exponents, we get:

(5^(2π‘₯) * 5^1 + (5/2)^(2π‘₯) / (5/2)^(2π‘₯)

(5^(2π‘₯) * 5 + (5/2)^(2π‘₯) / (5/2)^(2π‘₯)

(25 * 5^2π‘₯ + (5/2)^(2π‘₯) / (5/2)^(2π‘₯)

(25 * 5^2π‘₯ + 2^(2π‘₯) * 5^(-2π‘₯))

(25 * 5^(2π‘₯) + 1) / 5

25 * 5^(2π‘₯) / 5 + 1 / 5

5^(2π‘₯) * 5 + 1 / 5

25 * 5 + 1 / 5

125 + 1 / 5

126 / 5

So, the simplified expression is 126/5. Thank you for catching the error and helping with the correction.
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