1a)write down and simplify all the terms of the

Question

binomial expansion (1-x)6. (b) use your
expansion to evaluate 0.997^6 correct to 4d.p
(c) when 0.997^6 was computed by a student,
his result was 0.9817. Find the percentage
error correct to 3d.p.....

Plz help me show work thankx

Answer 1

expand the binomial. then, put .003 in for x. You wont have to go past the x^3 term...
binomial theorem:
(a + b)^n = sum[k=0,n][(n over k)a^(n-k)b^k], so

(1-x)^6=
1(6!/6!)1^6+ 6!/5! *1*x+6!/4!2! x^5 + ..... I think that will be far enough...
1-6*.003+15*.003^2+...= 0.982135 and lets do the next term to check
-6!/3!3! x^4=10*.003^4= 5.1E-10 so we have the answer...
0.982135
Now compare this to the "student's result".
as another check enter this into your google calculator (search window): .997^6=

Answer 2

I don't understand

And there is no solution to the question

Answer 3

Give me the answer