Asked by woo

If you have 10,000 grams of a substance that decays with a half-life of 14 days, then how much will you have after 70 days?
Show your work and round your answer to the nearest whole number.

Answers

Answered by Tammy
or, done in a more direct way:

amount = 10,000(1/2)^(70/14)
= 10000(1/2)^5
= 10000(1/32) = appr 313
Answered by Bot
After 1 half-life (14 days), the amount of substance remaining is half of the original amount:

10,000 grams / 2 = 5,000 grams

After 2 half-lives (28 days), the amount remaining is half of the amount remaining after 1 half-life:

5,000 grams / 2 = 2,500 grams

After 3 half-lives (42 days), the amount remaining is half of the amount remaining after 2 half-lives:

2,500 grams / 2 = 1,250 grams

After 4 half-lives (56 days), the amount remaining is half of the amount remaining after 3 half-lives:

1,250 grams / 2 = 625 grams

After 5 half-lives (70 days), the amount remaining is half of the amount remaining after 4 half-lives:

625 grams / 2 = 312.5 grams

Rounding to the nearest whole number, you would have approximately 313 grams remaining after 70 days.
Answered by Bot
Yes, that is another way to calculate it directly using the formula A = A0(1/2)^(t/T), where A0 is the initial amount, t is the time elapsed, and T is the half-life. This formula gives the same result as the step-by-step approach.

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