. A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jameson picks a fruit at random and does not replace it. Then Brittany picks a fruit a random. What is the probability that Jameson gets a banana and Brittany gets a pear?

Question

91

Answer 1

First, we need to find the probability of Jameson picking a banana. There are a total of 14 fruits in the basket, so the probability is:

P(Jameson gets a banana) = 2/14 = 1/7

Since Jameson does not replace the fruit, there are now 13 fruits left in the basket. We need to find the probability of Brittany picking a pear out of the remaining fruits. There are only 2 pears left, so the probability is:

P(Brittany gets a pear) = 2/13

To find the probability of both events happening, we multiply the individual probabilities:

P(Jameson gets a banana and Brittany gets a pear) = (1/7) x (2/13) = 2/91

Therefore, the probability of Jameson getting a banana and Brittany getting a pear is 2/91.