The pressure on the skin of the scuba diver at a depth of 30m can be calculated using the formula:
P = ρgh + Patm
where P is the total pressure, ρ is the density of the water, g is the acceleration due to gravity, h is the depth, and Patm is the atmospheric pressure.
Plugging in the values, we get:
P = (1030 kg/m3) x (9.81 m/s2) x (30m) + 1.013 x 105 Pa
P = 29226 + 1.013 x 105
P = 1.342 x 105 Pa
Therefore, the pressure on the skin of the scuba diver at a depth of 30m below the water surface is 1.342 x 105 Pa.
What would be the pressure on the skin of a scuba diver is he dives under the ocean at 30m below the water surface? The density of the sea water is about 1030 kg/m3. The atmospheric pressure is standard at 1.013 x 105 Pa.
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When a submarine dives to a depth of 100m , to how large a total pressure is its exterior surface subjected? The density of the sea water is about 1030 kg/m3. The atmospheric pressure is standard at 1.013 x 105 N/m2.
The total pressure on the exterior surface of a submarine at a depth of 100m can be calculated using the formula:
P = ρgh + Patm
where P is the total pressure, ρ is the density of the water, g is the acceleration due to gravity, h is the depth, and Patm is the atmospheric pressure.
Plugging in the values, we get:
P = (1030 kg/m3) x (9.81 m/s2) x (100m) + 1.013 x 105 N/m2
P = 101307 + 1.013 x 105
P = 2.046 x 105 N/m2
Therefore, the exterior surface of the submarine is subjected to a total pressure of 2.046 x 105 N/m2 at a depth of 100m.
P = ρgh + Patm
where P is the total pressure, ρ is the density of the water, g is the acceleration due to gravity, h is the depth, and Patm is the atmospheric pressure.
Plugging in the values, we get:
P = (1030 kg/m3) x (9.81 m/s2) x (100m) + 1.013 x 105 N/m2
P = 101307 + 1.013 x 105
P = 2.046 x 105 N/m2
Therefore, the exterior surface of the submarine is subjected to a total pressure of 2.046 x 105 N/m2 at a depth of 100m.
Atmospheric pressure is about 1.0 x 105 Pa. How large a force does the still air in the room exert on the inside of a window pane that 60cm x 120cm?
The force exerted by the still air in the room on the inside of the window pane can be calculated using the formula:
F = PA
where F is the force, P is the pressure, and A is the area.
Plugging in the values, we get:
F = (1.0 x 105 Pa) x (0.6m x 1.2m)
F = 72,000 Pa
Therefore, the still air in the room exerts a force of 72,000 Pa on the inside of the window pane. Note that Pa (Pascals) are equivalent to N/m2 (Newtons per square meter), so the force can also be expressed as:
F = 72,000 N/m2
F = PA
where F is the force, P is the pressure, and A is the area.
Plugging in the values, we get:
F = (1.0 x 105 Pa) x (0.6m x 1.2m)
F = 72,000 Pa
Therefore, the still air in the room exerts a force of 72,000 Pa on the inside of the window pane. Note that Pa (Pascals) are equivalent to N/m2 (Newtons per square meter), so the force can also be expressed as:
F = 72,000 N/m2
1 answer