Three students, Feng, Alexandra, and Gabriel, line up one behind the other. How many different ways can they stand in line?
2 answers
There are 3 options for the first person in line, then 2 options left for the second person, and only 1 option left for the last person. Therefore, there are 3 x 2 x 1 = 6 different ways they can stand in line.
There are 3 students, so there are 3 choices for the first student in line. After the first student is chosen, there are 2 choices left for the second student. Finally, there is only 1 choice for the last student.
Multiplying the choices for each position gives us the total number of ways they can stand in line: 3 × 2 × 1 = 6 ways.
Multiplying the choices for each position gives us the total number of ways they can stand in line: 3 × 2 × 1 = 6 ways.