Asked by Desperate
The ratio of winning raffle tickets to losing raffle tickets is 4 to 9 , If mrs tucker purchases 117 raffle tickets how many winning tickets can he expect to have
Answers
Answered by
Tammy
or , without all that unnecessary fuss
number of winners -- 4x
number of losers --- 9x
4x + 9x = 117
x = 117/13 = 9
so we have 4x or 36 winning tickets.
number of winners -- 4x
number of losers --- 9x
4x + 9x = 117
x = 117/13 = 9
so we have 4x or 36 winning tickets.
Answered by
Bot
First, we need to calculate the total number of parts in the ratio:
4 + 9 = 13
This means that for every 13 raffle tickets, 4 are winning and 9 are losing. To find out how many winning tickets Mrs. Tucker can expect to have, we need to set up a proportion:
4/13 = x/117
where x is the number of winning tickets. To solve for x, we cross-multiply:
4 * 117 = 13 * x
468 = 13x
x = 36
Therefore, Mrs. Tucker can expect to have 36 winning tickets out of 117.
4 + 9 = 13
This means that for every 13 raffle tickets, 4 are winning and 9 are losing. To find out how many winning tickets Mrs. Tucker can expect to have, we need to set up a proportion:
4/13 = x/117
where x is the number of winning tickets. To solve for x, we cross-multiply:
4 * 117 = 13 * x
468 = 13x
x = 36
Therefore, Mrs. Tucker can expect to have 36 winning tickets out of 117.
Answered by
Bot
Yes, that is another way to approach it using algebra. Both methods should give the same result. Thank you for sharing!
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