Asked by Sheilla
Simplify log4(16)-2log4(2) into single logarithm
Answers
Answered by
Bot
log4(16) - 2log4(2)
= log4(2^4) - log4(2^2)
= log4(2^4/2^2)
= log4(2^2)
= 2log4(2)
= log4(2^4) - log4(2^2)
= log4(2^4/2^2)
= log4(2^2)
= 2log4(2)
Answered by
Bot
The result obtained by the user is correct, but the steps shown are wrong, as the expression log4(16) - 2log4(2) cannot be simplified to 1 directly. Here is the correct explanation:
log4(16) - 2log4(2)
= log4(2^4) - log4(2^2)
= log4(2^4/2^2)
= log4(2^2)
= 2log4(2)
Hence, log4(16) - 2log4(2) simplified to a single logarithm is 2log4(2).
log4(16) - 2log4(2)
= log4(2^4) - log4(2^2)
= log4(2^4/2^2)
= log4(2^2)
= 2log4(2)
Hence, log4(16) - 2log4(2) simplified to a single logarithm is 2log4(2).
Answered by
Bot
Apologies for the error in my previous response. You are absolutely correct.
Let's simplify the expression log4(16) - 2log4(2) into a single logarithm:
log4(16) - 2log4(2)
= log4(2^4) - 2log4(2)
= 4log4(2) - 2log4(2)
= 2log4(2)
Since 4 can be expressed as 2^2, we know that log4(2) is equivalent to 1/2. Substituting in this value, we get:
2log4(2) = 2(1/2) = 1
Therefore, log4(16) - 2log4(2) simplifies to a single logarithm as 1.
Thank you for bringing this to our attention.
Let's simplify the expression log4(16) - 2log4(2) into a single logarithm:
log4(16) - 2log4(2)
= log4(2^4) - 2log4(2)
= 4log4(2) - 2log4(2)
= 2log4(2)
Since 4 can be expressed as 2^2, we know that log4(2) is equivalent to 1/2. Substituting in this value, we get:
2log4(2) = 2(1/2) = 1
Therefore, log4(16) - 2log4(2) simplifies to a single logarithm as 1.
Thank you for bringing this to our attention.
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