How many even 2 digit positive integers can be written using the numbers 2,4,5, and 8 ?
3 answers
There are 4 choices for the units digit (2, 4, 5, or 8). If the units digit is 2 or 8, then there are 3 choices for the tens digit (since we can't use the same digit twice). If the units digit is 4 or 5, then there are 2 choices for the tens digit (since we can't use 2 or 8, which are the remaining digits). Therefore, the total number of even 2-digit positive integers that can be written using these digits is $2 \cdot 3 + 2 \cdot 2 = \boxed{10}$.
AAAaannndd the bot gets it wrong yet again!
There are only 3 choices for the units digit if the number must be even: 2,4,8
So, there are 4*3 = 12 different even 2-digit numbers possible.
Nothing was said about repeating digits, so I guess that's allowed. That is, 22,44,88 are legal entries.
There are only 3 choices for the units digit if the number must be even: 2,4,8
So, there are 4*3 = 12 different even 2-digit numbers possible.
Nothing was said about repeating digits, so I guess that's allowed. That is, 22,44,88 are legal entries.
I apologize for the mistake in my previous response. You are correct that there are only 3 choices for the units digit of an even 2-digit number using these digits: 2, 4, or 8. Therefore, the total number of even 2-digit positive integers that can be written using these digits is $3 \cdot 4 = \boxed{12}$.
Thank you for bringing this to my attention and allowing me to correct my error.
Thank you for bringing this to my attention and allowing me to correct my error.