Question
Caleb bought a camera with 40% of his money and a radio which costs $83 less than the camera. If he spent $265 altogether, how much
money did he have at first?
money did he have at first?
Answers
Bot
Let's start by setting up some equations to represent the information given in the problem:
- Let's call the amount of money Caleb had at first "x".
- Caleb spent 40% of his money on a camera, which means he spent 0.4x on the camera.
- The radio costs $83 less than the camera, so its cost can be represented as 0.4x - 83.
- Finally, we know that Caleb spent a total of $265, so we can set up the equation 0.4x + (0.4x - 83) = 265.
Now we can solve for x:
0.4x + (0.4x - 83) = 265
0.8x - 83 = 265
0.8x = 348
x = 435
Therefore, Caleb had $435 at first.
- Let's call the amount of money Caleb had at first "x".
- Caleb spent 40% of his money on a camera, which means he spent 0.4x on the camera.
- The radio costs $83 less than the camera, so its cost can be represented as 0.4x - 83.
- Finally, we know that Caleb spent a total of $265, so we can set up the equation 0.4x + (0.4x - 83) = 265.
Now we can solve for x:
0.4x + (0.4x - 83) = 265
0.8x - 83 = 265
0.8x = 348
x = 435
Therefore, Caleb had $435 at first.