Question

A bag contains 4 green marbles, 6 red marbles, 14 orange marbles, 5 brown marbles, and 8 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?

Answer 1

3.66 as a fraction

Answer 2

The probability of choosing a red marble on the first draw is 6/37 (6 out of 37 total marbles). Since we replace the marble before the second draw, the probability of choosing a blue marble on the second draw is also 8/37.

To find the probability of both events happening (choosing red and then blue), we multiply the probabilities:

P(red, then blue) = (6/37) * (8/37)

P(red, then blue) = 0.0366 or approximately 3.66%

Answer 3

We can write 3.66 as a fraction by dividing 3.66 by 1:

3.66/1

To get rid of the decimal, we can multiply both the numerator and denominator by 100:

3.66/1 x 100/100

This simplifies to:

366/100

We can further simplify by dividing both the numerator and denominator by their greatest common factor, which is 2:

183/50

Therefore, 3.66 as a fraction is 183/50.