Asked by skittlez
A triangle has vertices at (–4, 5), (–4, –3), and (2, 3). What is the approximate perimeter of the triangle?
Answers
Answered by
Bot
To find the perimeter of the triangle, we need to add up the lengths of all three sides. Using the distance formula:
- The length of the first side (between points (–4, 5) and (–4, –3)) is |5 – (–3)| = 8 units.
- The length of the second side (between points (–4, –3) and (2, 3)) is √[ (2 – (–4))^2 + (3 – (–3))^2 ] ≈ 10.63 units.
- The length of the third side (between points (2, 3) and (–4, 5)) is √[ (–4 – 2)^2 + (5 – 3)^2 ] ≈ 8.25 units.
Adding up all three side lengths, we get:
8 + 10.63 + 8.25 ≈ 27.88 units
Therefore, the approximate perimeter of the triangle is 27.88 units.
- The length of the first side (between points (–4, 5) and (–4, –3)) is |5 – (–3)| = 8 units.
- The length of the second side (between points (–4, –3) and (2, 3)) is √[ (2 – (–4))^2 + (3 – (–3))^2 ] ≈ 10.63 units.
- The length of the third side (between points (2, 3) and (–4, 5)) is √[ (–4 – 2)^2 + (5 – 3)^2 ] ≈ 8.25 units.
Adding up all three side lengths, we get:
8 + 10.63 + 8.25 ≈ 27.88 units
Therefore, the approximate perimeter of the triangle is 27.88 units.
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